Program to find maximum number of courses we can take based on interval time in Python?

Suppose we have a list of intervals in the form [start, end], this is representing the start and end time of a course. We have to find the maximum number of courses we can take, assuming we can only take one course at a time and the start of a course needs to be later than the end of the last course.

So, if the input is like times = [[3, 6],[6, 9],[7, 8],[9, 11]], then the output will be 3, as we can take courses [[3, 6], [7, 8], [9, 11]]

To solve this, we will follow these steps:

• sort time based on ending time

• counter := 0, end := -1

• for i in range 0 to size of times, do

  • if times[i, 0] > end is non-zero, then

    • counter := counter + 1

    • end := times[i, 1]

• return counter

Let us see the following implementation to get better understanding:

Example

 Live Demo

class Solution:
   def solve(self, times):
      times.sort(key=lambda x: x[1])

      counter = 0
      end = -1

      for i in range(len(times)):
         if times[i][0] > end:
            counter += 1
            end = times[i][1]
      return counter

ob = Solution()
times = [
   [3, 6],
   [6, 9],
   [7, 8],
   [9, 11]
]
print(ob.solve(times))

Input

[ [3, 6],[6, 9],[7, 8],[9, 11]]

Output

3

Arnab Chakraborty

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Updated on: 10-Nov-2020

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