Program to find maximum score we can get in jump game in Python

Python Server Side Programming Programming

Suppose we have an array called nums and another value k. We are at index 0. In one move, we can jump at most k steps right without going outside the boundaries of the array. We want to reach the final index of the array. For jumping we get score, that is the sum of all nums[j] for each index j we visited in the array. We have to find the maximum score we can get.

So, if the input is like nums = [1,-2,-5,7,-6,4] k = 2, then the output will be 10 because, we jump in this sequence [1, -2, 7, 4], then we will get maximum point, and that is 10.

To solve this, we will follow these steps −

n := size of nums
scores := an array of size n and filled with 0
scores[0] := nums[0]
currMax := scores[0]
max_pt := 0
if n < 1, then
- return 0
if n is same as 1, then
- return last element of nums
for idx in range 1 to n - 1, do
- if max_pt >= idx - k, then
  - if currMax < scores[idx-1] and idx > 0, then
    - currMax := scores[idx-1]
    - max_pt := idx-1
- otherwise,
  - if idx - k > 0, then
    - currMax := scores[idx-k]
    - max_pt := idx - k
    - for p in range idx-k to idx, do
      - if scores[p] >= currMax, then
        max_pt := p
        currMax := scores[p]
- scores[idx] := currMax + nums[idx]
last element of scores := currMax + nums[-1]
return last element of scores

Example

Let us see the following implementation to get better understanding −

def solve(nums, k):
   n = len(nums)
   scores = [0] * n
   scores[0] = nums[0]
   currMax = scores[0]
   max_pt = 0

   if n < 1:
      return 0
   if n == 1:
      return nums[-1]

   for idx in range(1,n):
      if max_pt >= idx - k:
         if currMax < scores[idx-1] and idx > 0:
            currMax = scores[idx-1]
            max_pt = idx-1
      else:
         if idx - k > 0:
            currMax = scores[idx-k]
            max_pt = idx - k
            for p in range(idx-k, idx):
               if scores[p] >= currMax:
                  max_pt = p
                  currMax = scores[p]
      scores[idx] = currMax + nums[idx]
   scores[-1] = currMax + nums[-1]
   return scores[-1]

nums = [1,-2,-5,7,-6,4]
k = 2
print(solve(nums, k))

Input

[1,-2,-5,7,-6,4], 2

Output

Arnab Chakraborty

Published on 06-Oct-2021 11:21:46

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