Program to find maximum non negative product in a matrix in Python

Suppose we have a matrix of order m x n. Initially we are at the top-left corner cell (0, 0), and in each step, we can only move right or down in the matrix. Now among all possible paths from the top-left corner cell (0, 0) to bottom-right corner cell(m-1, n-1), we have to find the path with the maximum non-negative product. If the answer is too large, then return the maximum non-negative product modulo 10^9+7.

So, if the input is like

then the output will be 256 because the path is the colored one,

so product is [2 * 2 * (-4) * (-8) * 2] = 256.

To solve this, we will follow these steps −

• p := 10^9+7
• m := row count of matrix
• n := column count of matrix
• dp := a 2d matrix of which is of order with given matrix and fill with 0
• for i in range 0 to m - 1, do
  • for j in range 0 to n - 1, do
    • if i is same as 0 and j is same as 0, then
      • dp[i, j] := make a pair (matrix[i, j], matrix[i, j])
    • otherwise when i is same as 0, then
      • ans1 := dp[i, j-1, 0] * matrix[i, j]
      • dp[i, j] := make a pair (ans1, ans1)
    • otherwise when j is same as 0, then
      • ans1 := dp[i-1, j, 0] * matrix[i, j]
      • dp[i, j] := make a pair (ans1, ans1)
    • otherwise,
      • ans1 := dp[i-1, j, 0] * matrix[i, j]
      • ans2 := dp[i-1, j, 1] * matrix[i, j]
      • ans3 := dp[i, j-1, 0] * matrix[i, j]
      • ans4 := dp[i, j-1, 1] * matrix[i, j]
      • maximum := maximum of ans1, ans2, ans3 and ans4
      • minimum := minimum of ans1, ans2, ans3 and ans4
      • if maximum < 0, then
        • dp[i, j] := make a pair (minimum, minimum)
      • otherwise when minimum > 0, then
        • dp[i, j] := make a pair (maximum, maximum)
      • otherwise,
        • dp[i, j] := make a pair (maximum, minimum)
• if dp[m-1, n-1, 0] < 0, then
  • return -1
• otherwise,
  • return dp[m-1, n-1, 0] % p

Example

Let us see the following implementation to get better understanding −

def solve(matrix):
   p = 1e9+7
   m = len(matrix)
   n = len(matrix[0])

   dp = [[0 for _ in range(n)] for _ in range(m)]

   for i in range(m):
      for j in range(n):
         if i == 0 and j == 0:
            dp[i][j] = [matrix[i][j], matrix[i][j]]

         elif i == 0:
            ans1 = dp[i][j-1][0] * matrix[i][j]
            dp[i][j] = [ans1, ans1]

         elif j == 0:
            ans1 = dp[i-1][j][0] * matrix[i][j]
            dp[i][j] = [ans1, ans1]

         else:
            ans1 = dp[i-1][j][0] * matrix[i][j]
            ans2 = dp[i-1][j][1] * matrix[i][j]
            ans3 = dp[i][j-1][0] * matrix[i][j]
            ans4 = dp[i][j-1][1] * matrix[i][j]
            maximum = max(ans1, ans2, ans3, ans4)
            minimum = min(ans1, ans2, ans3 ,ans4)
            if maximum < 0:
               dp[i][j] = [minimum, minimum]
            elif minimum > 0 :
               dp[i][j] = [maximum, maximum]
            else:
               dp[i][j] = [maximum, minimum]

   if dp[m-1][n-1][0] < 0:
      return -1
   else:
      return int(dp[m-1][n-1][0] % p)

matrix = [[2,-4,2],[2,-4,2],[4,-8,2]]
print(solve(matrix))

Input

"pqpqrrr"

Output

256

Arnab Chakraborty

Updated on: 04-Oct-2021

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