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Suppose we have a non-negative value n, we have to find the length of the longest consecutive run of 1s in its binary representation.

So, if the input is like n = 1469, then the output will be 4, because binary representation of 156 is "10110111101", so there are four consecutive 1s

To solve this, we will follow these steps −

- count := 0
- while n is not same as 0, do
- n := n AND (n after shifting one bit to the left)
- count := count + 1

- return count

Let us see the following implementation to get better understanding −

def solve(n): count = 0 while n != 0: n = n & (n << 1) count = count + 1 return count n = 1469 print(solve(n))

1469

4

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