Program to find ith element by rotating k times to right

Suppose we have an array nums, and a value k and another value i. We have to find the element at index i after rotating elements of nums, k number of times to the right.

So, if the input is like nums = [2,7,9,8,10] k = 3 i = 2, then the output will be 10 because after 3rd rotation array will be [9,8,10,2,7], so now the ith element will be nums[2] = 10.

To solve this, we will follow these steps −

  • for r in range 0 to k, do
    • delete last element from nums and insert that deleted element into nums at position 0
  • return nums[i]


Let us see the following implementation to get better understanding

def solve(nums, k, i):
   for r in range(k):
      nums.insert(0, nums.pop())
   return nums[i]

nums = [2,7,9,8,10]
k = 3
i = 2
print(solve(nums, k, i))


[2,7,9,8,10] , 3, 2



Updated on: 12-Oct-2021


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