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Suppose we have a string s that is representing alphabet characters and a number k. We have to find the number of palindromes where we can construct of length k using only letters in s. And we can use these letters more than once if we want.

So, if the input is like s = "xy", k = 4, then the output will be 4 as the palindromes are [xxxx, yyyy, xyyx, yxxy].

To solve this, we will follow these steps −

- n := quotient of k/2
- x := number of unique characters in s
- return x^(n + k mod 2)

Let us see the following implementation to get better understanding −

class Solution: def solve(self, s, k): n=k//2 return len(set(s))**(n+k%2) s = "xy" k = 4 ob = Solution() print(ob.solve(s, k))

"xy",4

4

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