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C++ Program to count number of characters to be removed to get good string
Suppose we have a string S. S contains two types of characters in S, the 'x' and 'a'. We have to count what will be the longest string remaining after removal of few characters in S so that it becomes good string. A string is good if it has strictly more than the half of its length filled with character 'a'.
So, if the input is like S = "xaxxxxa", then the output will be 3, because if we remove 4 'x's, the string will be "xaa" and this is a good string whose length is 3.
Steps
To solve this, we will follow these steps −
x := 2 * count the number of 'a' in S n := size of S return minimum of n and x
Example
Let us see the following implementation to get better understanding −
#include <bits/stdc++.h>
using namespace std;
int solve(string S) {
int x = 2 * count(S.begin(), S.end(), 'a') - 1;
int n = S.size();
return min(n, x);
}
int main() {
string S = "xaxxxxa";
cout << solve(S) << endl;
}Input
"xaxxxxa"
Output
3
Updated on: 04-Mar-2022
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