# Program to check sublist sum is strictly greater than the total sum of given list Python

Suppose we have a list of numbers called nums, we have to check whether there is a sublist such that its sum is strictly greater than the total sum of the list.

So, if the input is like nums = [1, −2, 3, 4], then the output will be True, as the sum of the list is 6 and the sum of the sublist [3, 5] is 8 which is strictly larger.

To solve this, we will follow these steps −

• total := sum of elements nums

• s := 0

• for each i in nums, do

• s := s + i

• if s < 0, then

• return True

• s := 0

• i := size of nums − 1

• while i > −1, do

• s := s + nums[i]

• if s < 0, then

• return True

• i := i − 1

• return False

Let us see the following implementation to get better understanding −

## Example

Live Demo

class Solution:
def solve(self, nums):
total = sum(nums)
s = 0
for i in nums:
s += i
if s < 0:
return True
s = 0
i = len(nums) − 1
while i > −1:
s += nums[i]
if s < 0:
return True
i = i − 1
return False

ob1 = Solution()
nums = [2, -4, 3, 5]
print(ob1.solve(nums))

## Input

[2, −4, 3, 5]

## Output

True