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Program to check sublist sum is strictly greater than the total sum of given list Python
Suppose we have a list of numbers called nums, we have to check whether there is a sublist such that its sum is strictly greater than the total sum of the list.
So, if the input is like nums = [1, −2, 3, 4], then the output will be True, as the sum of the list is 6 and the sum of the sublist [3, 5] is 8 which is strictly larger.
To solve this, we will follow these steps −
total := sum of elements nums
s := 0
for each i in nums, do
s := s + i
if s < 0, then
return True
s := 0
i := size of nums − 1
while i > −1, do
s := s + nums[i]
if s < 0, then
return True
i := i − 1
return False
Let us see the following implementation to get better understanding −
Example
class Solution: def solve(self, nums): total = sum(nums) s = 0 for i in nums: s += i if s < 0: return True s = 0 i = len(nums) − 1 while i > −1: s += nums[i] if s < 0: return True i = i − 1 return False ob1 = Solution() nums = [2, -4, 3, 5] print(ob1.solve(nums))
Input
[2, −4, 3, 5]
Output
True
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