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# Program to find sum of contiguous sublist with maximum sum in Python

Suppose we have an array A. We have to find the contiguous sublist which has the maximum sum, and also return its sum. So if the array A is like A = [-2,1,-3,4,-1,2,1,-5,4], then the sum will be 6. And the subarray will be [4, -1, 2, 1].

To solve this we will try to use Dynamic programming approach.

define an array dp same as the size of A, and fill it with 0

dp[0] := A[0]

for i := 1 to size of A – 1

dp[i] := maximum of dp[i – 1] + A[i] and A[i]

return max in dp

Let us see the following implementation to get better understanding −

## Example

class Solution(object): def solve(self, nums): dp = [0 for i in range(len(nums))] dp[0] = nums[0] for i in range(1,len(nums)): dp[i] = max(dp[i-1]+nums[i],nums[i]) return max(dp) nums = [-2,1,-3,7,-2,2,1,-5,4] ob1 = Solution() print(ob1.solve(nums))

## Input

[-2,1,-3,7,-2,2,1,-5,4]

## Output

8

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