- Trending Categories
- Data Structure
- Networking
- RDBMS
- Operating System
- Java
- iOS
- HTML
- CSS
- Android
- Python
- C Programming
- C++
- C#
- MongoDB
- MySQL
- Javascript
- PHP

- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who

Suppose we have sequence of numbers nums, and another two arrays l and r of size m, these l and r are representing range queries like [l[i], r[i]]. We have to find a Boolean sequence ans, where ans[i] is true when the subarray nums[l[i]], nums[l[i] + 1], ... nums[r[i] - 1], nums[r[i]] can be arranged to generate an arithmetic sequence, otherwise false.

A sequence is said to be arithmetic, if it consists of at least two elements, and the difference between every two consecutive elements is the same. For example, some arithmetic sequences are: [2, 4, 6, 8, 10], [5, 5, 5, 5], [4, -2, -8, -14], but not [2, 2, 3, 6, 9].

So, if the input is like nums = [6,8,7,11,5,9], l = [0,0,2], r = [2,3,5], then the output will be [True, False, True] because −

for query [0, 2], the sequence is [6,8,7], can be rearranged as [6,7,8], this is valid

for query [0, 3], the sequence is [6,8,7,11], cannot be rearranged in arithmetic sequence

for query [2, 5], the sequence is [7,11,5,9], can be rearranged as [5,7,9,11], this is valid

To solve this, we will follow these steps −

new := a list of size same as l and fill with all true values

for i in range 0 to size of l - 1, do

data := sublist of nums from index l[i] to r[i]

sort the list data

d := a new list

for j in range 0 to size of data - 2, do

insert data[j+1] - data[j] at the end of d

d := a new list from a new set from d

if size of d is not same as 1, then

new[i] := False

return new

Let us see the following implementation to get better understanding −

def solve(nums, l, r): new = [True]*len(l) for i in range(len(l)): data = nums[l[i]:r[i]+1] data.sort() d = [] for j in range(len(data) - 1): d.append(data[j+1] - data[j]) d = list(set(d)) if len(d) != 1: new[i] = False return new nums = [6,8,7,11,5,9] l = [0,0,2] r = [2,3,5] print(solve(nums, l, r))

[6,8,7,11,5,9], [0,0,2], [2,3,5]

[True,False,True]

- Related Questions & Answers
- Program to check we can make arithmetic progression from sequence in Python
- Check if the elements of the array can be rearranged to form a sequence of numbers or not in JavaScript
- Program to find removed term from arithmetic sequence in Python
- Check if a string can be rearranged to form special palindrome in Python
- Program to check we can form array from pieces or not in Python
- Program to check whether one point can be converted to another or not in Python
- Program to check words can be found in matrix character board or not in Python
- Program to check a string can be split into three palindromes or not in Python
- Program to check two strings can be equal by swapping characters or not in Python
- Program to check n can be shown as sum of k or not in Python
- Program to check how many queries finds valid arithmetic sequence in Python
- Program to check whether two trees can be formed by swapping nodes or not in Python
- Program to check n can be represented as sum of k primes or not in Python
- Program to check all tasks can be executed using given server cores or not in Python
- Program to check we can visit any city from any city or not in Python

Advertisements