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C++ code to check array can be formed from Equal Not-Equal sequence or not
Suppose we have a string S of length . Consider there are n numbers and they are arranged in a circle. We do not know the values of these numbers but if S[i] = 'E' it indicates ith and (i+1)th numbers are same, but if that is 'N' then they are different. From S we have to check whether we can recreate the sequence or not.
So, if the input is like S = "ENNEENE", then the output will be True, because we can assign values like [15,15,4,20,20,20,15].
Steps
To solve this, we will follow these steps −
if S has single 'N', then: return false return true
Example
Let us see the following implementation to get better understanding −
#include<bits/stdc++.h>
using namespace std;
bool solve(string S){
if (count(S.begin(), S.end(), 'N') == 1)
return false;
return true;
}
int main(){
string S = "ENNEENE";
cout << solve(S) << endl;
}Input
"ENNEENE"
Output
1
Updated on: 11-Mar-2022
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