Print missing elements that lie in range 0 – 99

It will display the missing values from the given set entered by the user

Given : array = {88, 105, 3, 2, 200, 0, 10};
Output : 1 4-9 11-87 89-99

Algorithm

START
STEP 1-> Take an array with elements, bool flag[MAX] to Fale, int i, j, n to size of array
Step 2-> Loop For from I to 0 and i=0
      Set flag[array[i]]=true
   End IF
Step 3 -> End For Loop
Step 4 -> Loop For from i to 0 and i End For Loop
STOP

Example

#include 
#define MAX 100
int main(int argc, char const *argv[]) {
   int array[] = {88, 105, 3, 2, 200, 0, 10};
   bool flag[MAX] = { false }; //Initializing all the values of flag as false
   int i, j, n;
   n = sizeof(array)/sizeof(array[0]);
   for (i = 0; i =0) {
         flag[array[i]] = true; //Making the value of the elements present in an array as true, So missing will remain false
      }
   }
   for (i = 0; i ", i);
         else //For printing the missing range
            printf("%d-%d
", i, j-1);
         i = j; //Initializing the range's last value to start from that number
      }
   }
   return 0;
}

Output

If we run the above program then it will generate the following output

1
4-9
11-87
89-99