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Python Program that print elements common at specified index of list elements
When it is required to print the elements common at a specific index in a list of strings, a ‘min’ method, list comprehension and a Boolean flag value can be used.
Example
Below is a demonstration of the same
my_list = ["week", "seek", "beek", "reek", 'meek', 'peek']
print("The list is :")
print(my_list)
min_length = min(len(element) for element in my_list)
my_result = []
for index in range(0, min_length):
flag = True
for element in my_list:
if element[index] != my_list[0][index]:
flag = False
break
if flag:
my_result.append(my_list[0][index])
print("The result is :")
print(my_result)Output
The list is : ['week', 'seek', 'beek', 'reek', 'meek', 'peek'] The result is : ['e', 'e', 'k']
Explanation
A list of strings is defined and is displayed on the console.
The list comprehension is used to iterate through elements of the list and get the minimum of lengths of elements.
This is assigned to a variable.
An empty list is defined.
The list is iterated over, and a Boolean value is assigned to 'True'.
The elements of the list are iterated again, and if the element at a specific index is not equal to character at a specific index, the Boolean value is assigned to 'False'.
The control breaks out of the loop.
Depending on this Boolean value, the character is appended to the empty list.
This is displayed as output on the console.
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