Print all Prime Quadruplet of a number less than it in C++

In this problem, we are given a positive integer N, and we have to print all prime quadruplet less than or equal to n.

Prime quadruplets are the set of four prime numbers calculated as {p, p⁺², p⁺⁶, p⁺⁸}. Example − 5 7 11 13.

Let’s take an example to understand the problem −

Input: N = 15
Output: 5 7 11 13.

To solve this problem, a simple approach is to generate all quadruplets of prime number p and check if all p, p⁺², p⁺⁶, p⁺⁸ are prime numbers. This solution is easy but is more complex for the compiler.

Another efficient approach is to fond all prime numbers (using the sieve of Eratosthenes) and store them in an array up to a certain range. And traverse the array and check p, p⁺², p⁺⁶, p⁺⁸ are prime or not and print if they all are prime.

Example

Live Demo

#include <bits/stdc++.h>
using namespace std;
#define MAX 100000
bool prime[MAX];
void primeNumberGenerator() {
   memset(prime, true, sizeof(prime));
   for (int p = 2; p * p < MAX; p++) {
      if (prime[p] == true) {
         for (int i = p * 2; i < MAX; i += p)
            prime[i] = false;
      }
   }
}
void printPrimeQuadruplet(int n) {
   for (int i = 0; i < n - 7; i++) {
      if (prime[i] && prime[i + 2] && prime[i + 6] && prime[i + 8]) {
         cout<<i<<" "<<i+2<<" "<<i+6<<" "<<i+8<<endl;
      }
   }
}
int main() {
   primeNumberGenerator();
   int n = 42;
   cout<<"All prime Quadruplets are :\n";
   printPrimeQuadruplet(20);
   return 0;
}