Recursive program to print all numbers less than N which consist of digits 1 or 3 only in C++

We are given an integer variable as N storing the positive integer type value. The task is to recursively print all the numbers less than given value N having digit 1, 3 or the combination of both.

Let us see various input output scenarios for this −

Input − int num = 40

Output − Recursive program to print all numbers less than N which consist of digits 1 or 3 only are: 33 31 13 11 3 1

Explanation − we are given a positive integer value as 40 stored in a variable num. Now, we will recursively find out all the numbers containing digits 1, 3 or both and those numbers less than 40 are 1, 3, 11, 13, 31, 33

Input − int num = 5

Output − Recursive program to print all numbers less than N which consist of digits 1 or 3 only are: 3 1

Input − int num = 1

Output − Wrong Input

Explanation − we are given a positive integer value as 1 stored in a variable num. Now, we will recursively find out all the numbers containing digits 1, 3 or both and those numbers less than 1 are 0 because the only positive integer less than 1 is 0 therefore, output is wrong input.

Approach used in the below program is as follows

Input an integer variable as num. Pass it to the function Recursive_Numbers(num) by passing num as the parameter to the function.
Inside the function Recursive_Numbers(num)
- Declare a variable as check of type bool and set it with 1.
- Check IF num greater than 0 then start WHILE temp greater than 0 AND check to 1. Set digit to temp % 10.
- Check IF digit not equals 1 AND digit not equals to 3 then set check to 0. Set temp = temp / 10.
- Check IF check is 1 then print num.
- Make a recursive call to the function Recursive_Numbers(num - 1)

Example

#include <iostream>
using namespace std;
void Recursive_Numbers(int num){
   bool check = 1;
   int temp = num;
   if(num > 0){
      while(temp > 0 && check == 1){
         int digit = temp % 10;
         if (digit != 1 && digit != 3){
            check = 0;
         }
         temp = temp / 10;
      }
      if(check == 1){
         cout<< num << " ";
      }
      Recursive_Numbers(num - 1);
   }
}
int main(){
   int num = 40;
   if(num <= 1){
      cout<<"Wrong input";
   }
   else{
      cout<<"Recursive program to print all numbers less than N which consist of digits 1 or 3 only are: ";
      Recursive_Numbers(num);
   }
   return 0;
}

Output

If we run the above code it will generate the following Output

Recursive program to print all numbers less than N which consist of digits 1 or 3 only are: 33 31
13 11 3 1

Sunidhi Bansal

Published on 02-Nov-2021 05:53:00

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