PHP program to check if a given number is present in an infinite series or not
To check if a given number is present in an infinite series or not, the PHP code is as follows −
Example
Live Demo
<?php
function contains_val($m, $n, $o){
if ($m == $n)
return true;
if (($n - $m) * $o > 0 && ($n - $m) % $o == 0)
return true;
return false;
}
$m = 3; $n = 5; $o = 9;
if (contains_val($m, $n, $o))
echo "The number is present in the infinite series";
else
echo "The number is not present in the infinite series";
?>Output
The number is not present in the infinite series
Above, three variables are defined, and the function is called by passing these three values −
$m = 3; $n = 5; $o = 9;
A function named ‘contains_val’ is defined, that takes these three variables. The first two variables
are compared, and if they are equal, ‘true’ is returned. Otherwise, if the different between the first
two variables with the product of the third number is greater than 0 and the different between the
first two variables modulus the third number is 0, ‘true’ is returned. Otherwise, the function returns
false −
function contains_val($m, $n, $o){
if ($m == $n)
return true;
if (($n - $m) * $o > 0 && ($n - $m) % $o == 0)
return true;
return false;
}
Published on 17-Aug-2020 12:16:53
