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Golang program to check if k’th bit is set for a given number or not.
Examples
Consider n = 20(00010100), k = 3
So, the result after turning off the 3rd bit => 00010000 & (1 << (4-1)) != 0
Approach to solve this problem −
Step 1 − Define a method, where n and k would be the arguments, returns type is int.
Step 2 − Perform AND operation with n & (1<<(k-1)).
Step 3 − If obtained number is not 0 then Kth of n is set else not set.
Example
package main import ( "fmt" "strconv" ) func CheckKthBitSet(n, k int) int { return n & (1 << (k-1)) } func main(){ var n = 20 var k = 3 fmt.Printf("Binary of %d is: %s.\n", n, strconv.FormatInt(int64(n), 2)) flag := CheckKthBitSet(n, k) if flag !=0 { fmt.Printf("%d rd bit of %d is aleady set.\n", k, n) } else { fmt.Printf("%d rd bit of %d is not set.\n", k, n) } }
Output
Binary of 20 is: 10100. 3 th bit of 20 is aleady set.
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