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Write two Pythagorean triplets each having one of the numbers as 5.
Given:
A number $5$ is one number of the Pythagorean triplets.
To do:
We have to write two such Pythagorean triplets.
Solution:
One number of the Pythagorean triplets is $5$.
We know,
Pythagorean triplets $=m^2-1, 2m, m^2+1$
Here,
$m^2+1=5$
$\Rightarrow m^2=5-1=4$
$\Rightarrow m=2$
If $m=2$, then
$\Rightarrow m^2-1=2^2-1=4-1=3$
$\Rightarrow m^2+1=2^2+1=4+1=5$
Here, 5 is the hypotenuse.
If we take 5 as one of the legs, then,
We know that,
$13^2=169$
$=144+25$
$=12^2+5^2$
Therefore, $(5, 12, 13)$ is a Pythagorean triplet.
Hence, the required Pythagorean triplets are $(3, 4, 5)$ and $(5, 12, 13)$.
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