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Given that one of the numbers of a Pythagorean triplet is 18, find the other two numbers.
Given :That one of the numbers of a Pythagorean triplet is 18
To Do: Find the other two numbers of the triplet
.
Solution:
Given, one number is 18
$2m = 18$
$m = 9$
Second number = $m^2+1 = 9^2+1 = 81+1 = 82$
Third number = $m^2-1 = 9^2-1 = 81-1 = 80$
Pythagorean triplet is (18, 80, 82)
Updated on: 10-Oct-2022
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