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What force acting on an area of $80\ m^2$ will produce a pressure of $400\ Pa$?
Given:
Area $A=80\ m^2$
Pressure $P=400\ Pa$
Let $F$ be the acting force.
We know, $Pressure\ P=\frac{Force(F)}{Area(A)}$
Or $400=\frac{F}{80}$
Or $F=400\times80$
Or $F=32000\ N$
Therefore, $32000\ N$ is the acting force on the given area.
Updated on: 10-Oct-2022
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