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What force acting on an area of $20\ m^2$ will produce a pressure of $500\ Pa$?
Given:
Area $A=20\ m^2$
Pressure $P=500\ Pa$
Let $F$ be the acting force.
We know, $Pressure\ P=\frac{Force(F)}{Area(A)}$
Or $500=\frac{F}{20}$
Or $F=500\times20$
Or $F=10000\ N$
Therefore, $10000\ N$ is the acting force on the given area.
Updated on: 10-Oct-2022
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