What force acting on an area of $6\ m^2$ will produce a pressure of $20\ Pa$?

Given: 

Area $A=6\ m^2$

Pressure $P=20\ Pa$

Let $F$ be the acting force.

We know, $Pressure\ P=\frac{Force(F)}{Area(A)}$

Or $20=\frac{F}{6}$

Or $F=20\times6$

Or $F=120\ N$

Therefore, $120\ N$ is the acting force on the given area.

Updated on: 10-Oct-2022

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