The minimum temperature in °C for the first 10 days of December 2010 in a certain city was10°, 8°, 9°, 11°, 8°, 7°, 5°, 2°, 3°, 1°(a) Calculate the mean minimum temperature for this period.(b) Calculate range of temperature.(c) What was the minimum temperature?(d) On how many days the temperature was more than mean temperature?

a)

$ \begin{array}{l}
The\ mean\ minimum\ temperature\ for\ this\ period\ =\ \frac{Sum\ of\ temp.\ of\ all\ days}{Total\ no.\ of\ days}\\
\\
\\
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The\ mean\ minimum\ temperature\ for\ this\ period\ =\ \frac{10^{\circ } +8^{\circ } +9^{\circ } +11^{\circ } +8^{\circ } +7^{\circ } +5^{\circ } +2^{\circ } +3^{\circ } +1^{\circ }}{10}\\
\\
\\
The\ mean\ minimum\ temperature\ for\ this\ period\ =\ \frac{64^{\circ }}{10}\\
\\
\\
The\ mean\ minimum\ temperature\ for\ this\ period\ =\ 6.4^{\circ }
\end{array}$

b) The range is the difference between the lowest and the highest observation in a data set.

Range = Highest temperature - Lowest temperature

Range = 11^o - 1^o = 10^o 

c) Minimum temperature = 1^o 

d) Number of days having temperature more than mean temperature = 6 days

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Updated on: 10-Oct-2022

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