The temperature of a city drops by $ 15^{\circ} \mathrm{C} $ in one month. If the present day temperature is $ -4^{\circ} \mathrm{C} $, what was the temperature one month ago?
Given:
The temperature of a city drops by \( 15^{\circ} \mathrm{C} \) in one month.
The present day temperature is \( -4^{\circ} \mathrm{C} \).
To do:
We have to find the temperature one month ago.
Solution:
Let the temperature of the city last month be $x$.
This implies,
The present day temperature of the city $=$ Temperature of the city last month day$-$ Drop in the temperature in one month.
$\Rightarrow -4^{\circ} \mathrm{C}=x-15^{\circ} \mathrm{C}$
$x=(15-4)^{\circ} \mathrm{C}$
$=11^{\circ} \mathrm{C}$.
The temperature of the city one month ago is $11^{\circ} \mathrm{C}$.
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