The discriminant of $6x^2+bx+2=0$ is 1, then what is the value of b?

Given:  The equation $6x^2+bx=2=0$ has discriminant 1.

To do:  We need to find the value of b.

Solution:

we know discriminant of quadratic $ax^{2}  + bx + c = 0$

                                                                $ax^ 2 + bx + c  = 0, is    b^{2} -4acb^ 2 −4ac$

Here, a = 6, b = b, c = 2

It is given $b^{2}  - 4ac = 0b^ 2 −4ac=0$

So,$ b^{2} - 4\times 6\times 1$

= $1b^ 2 −4\times6\times2$

=$1 b^{2}  - 24 = 1b^ 2 −48$

=$1 b^{2}  = 25b ^2 =49a$

$b = +7$ or $b = -7$

So, the answer is either the value of b is +7 or - 7

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Updated on: 10-Oct-2022

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