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Test the divisibility of the following numbers by 6 a) 5634 b) 65990
Given: The numbers are
a) 5634
b) 65990
To do: Test the divisibility of the given numbers by 6.
Solution:
Divisibility rule for 6
If a number ends in a 0, 2, 4, 6 or 8, it is divisible by 2
If a number is such that the sum of its digits is divisible by 3, then the number is divisible by 3.
If a number is divisible by both 2 and 3, then it is divisible by 6.
a) 5634
5634 ends in 4. So the number 5634 is divisible by 2.
$5 + 6 + 3 + 4 = 18$. 18 is divisible by 3. So the number 5634 is divisible by 3
As it is divisible both by 2 and 3, the number 5634 is divisible by 6.
b) 65990
65990 ends in 0. So the number 65990 is divisible by 2.
$6 + 5 + 9 + 9 + 0 = 29$. 29 is NOT divisible by 3. So the number 65990 is NOT divisible by 3
As it is divisible by 2 but not by 3, the number 65990 is NOT divisible by 6.
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