Subtract the cube of $-2$ from the cube of $2$.

Given :

The given statement is 'subtract the cube of $-2$ from the cube of $2$.'

To do :

We have to find the cubes of the given numbers and subtract them.

Solution :

Cube of $2 = 2^3 = 2 \times 2 \times 2 = 8$

Cube of $-2 = (-2)^3=-2 \times -2 \times -2 = 4 \times -2 = -8$        $[- \times - = +]$

Cube of $2 -$ cube of $(-2)$ = $8-(-8) = 8+8 = 16$.

Therefore, the resultant number is 16.

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Updated on: 10-Oct-2022

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