Solve:$x^{2} \ +\ 5x\ +\ 6\ =\ 0$

Given: $x^{2} \ +\ 5x\ +\ 6\ =\ 0$

To find: Here we have to find the value of $x$ in the given equation $x^{2} \ +\ 5x\ +\ 6\ =\ 0$.

Solution:

$x^{2} \ +\ 5x\ +\ 6\ =\ 0$

$x^{2} \ +\ 3x\ +\ 2x\ +\ 6\ =\ 0$

$x( x\ +\ 3) \ +\ 2( x\ +\ 3) \ =\ 0$

$( x\ +\ 3)( x\ +\ 2) \ =\ 0$

Therefore,

$\mathbf{x\ =\ -\ 2}$   or   $\mathbf{x\ =\ -\ 3}$

So, value of x is $-$2 and $-$3.

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Updated on: 10-Oct-2022

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