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Solve for $x$:$ 1-(x-2)-[(x-3)-(x-1)]=0 $
Given: Expression: $1-(x-2)-[(x-3)-(x-1)]=0$
To do:
To solve the expression $1-(x-2)-[(x-3)-(x-1)]=0$
Solution:
$1-(x-2)-[(x-3)-(x-1)]=0$
$\Rightarrow1-(x-2)-[(x-3-x+1)]=0$
$\Rightarrow1-(x-2)-(-2)=0$
$\Rightarrow1-(x-2)+2=0$
$\Rightarrow1-x+2+2=0$
$\Rightarrow5-x=0$
$\Rightarrow\ x=5$
Thus, the value of $x=5$.
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