Solve for $x$:$ 1-(x-2)-[(x-3)-(x-1)]=0 $


Given:  Expression: $1-(x-2)-[(x-3)-(x-1)]=0$

To do: 

To solve the expression $1-(x-2)-[(x-3)-(x-1)]=0$

Solution:

$1-(x-2)-[(x-3)-(x-1)]=0$

$\Rightarrow1-(x-2)-[(x-3-x+1)]=0$

$\Rightarrow1-(x-2)-(-2)=0$

$\Rightarrow1-(x-2)+2=0$

$\Rightarrow1-x+2+2=0$

$\Rightarrow5-x=0$

$\Rightarrow\ x=5$

Thus, the value of $x=5$.

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Updated on: 10-Oct-2022

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