Solve:
$(2p\ +\ 3q\ -\ 3r)2$

Given: $(2p\ +\ 3q\ -\ 3r)2$

To find: Here we have to find the value of the given expression $(2p\ +\ 3q\ -\ 3r)2$.

Solution:

$(2p\ +\ 3q\ -\ 3r)2$

$=\ 2(2p) \ +\ 2( 3q) \ -\ 2( 3r)$

$=\mathbf{\ 4p\ +\ 6q\ -\ 6r}$

So, value of the given expression is $4p\ +\ 6q\ -\ 6r$.

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Updated on: 10-Oct-2022

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