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Solve: $2+2-2\times2-9-( \frac{3}{2})$%=?
Given: $2+2-2\times2-9-( \frac{3}{2})$%=?
To do: To solve: $2+2-2\times2-9-( \frac{3}{2})$%=?
Solution:
$2+2-2\times2-9-( \frac{3}{2})$%=?
$=4-4-9-\frac{3}{2}\times100$
$=-9-150$
$=-159$
Thus, $2+2-2\times2-9-( \frac{3}{2})=-159$.
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