In order to obtain a magnification of, −1.5 with a concave mirror of focal length 16 cm, the object will have to be placed at a distance(a) between 6 cm and 16 cm (b) between 32 cm and 16 cm(c) between 48 cm and 32 cm (d) beyond 64 cm

Given:

Magnification, $m$ =$-$1.5

Here, magnification is with the positive sign $(-)$, which implies that the image is real and inverted.

$\because m>1\Rightarrow $ the size of the image is greater than that of the object.

In the case of the concave mirror, both of the above-mentioned conditions are only possible when the object is placed between the focus $(F)$ and the centre of curvature $(C)$ in front of the mirror.

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Updated on: 10-Oct-2022

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