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In order to obtain a magnification of, $-$0.75 with a convex lens of focal length 8 cm, the object should be placed:(a) at less than 8 cm (b) between 8 cm and 16 cm(c) beyond 16 cm (d) at 16 cm
(c) Beyond 16 cm
Explanation
Since, the magnification of the image is negative, it means the nature of the image is real and inverted. Also, size of the image is less than 1 which is 0.75, it implies that the size of the image is diminished (smaller than the object).
Thus, the image of this nature and size is formed when the object is placed beyond $2f$ of the convex lens.
Here, the focal length $f$ is 8 cm, then the $2f$ will be 16 cm $(2\times {12})$, so the object should be placed beyond 16 cm.
Image is posted for reference only
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