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In an AP five times of $5^{th}$ term is equal to ten times the $10^{th}$ term, show that its 15th term is zero.
Given: In an AP five times of $5^{th}$ term is equal to ten times the $10^{th}$ term.
To do: To show that its $15^{th}$ term is zero.
Solution:
$5^{th}$ Term $=a+4d$
$10^{th}$ Term $=a+9d$
According to question,
$5(a+4d) = 10(a+9d)$
$\Rightarrow 5a+20d = 10a+90d$
$\Rightarrow 10a+90d-5a-20d =0$
$\Rightarrow 5a+70d =0$
$\Rightarrow 5( a+14d) =0$
$\Rightarrow a+14d =\frac{0}{5}$
$\Rightarrow a+14d =0$
Which is $15^{th}$ Term.
Hence Proved.
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