In a hot water heating system, there is a cylindrical pipe of length $28\ m$ and diameter $5\ cm$. Find the total radiating surface in the system.
Given:
In a hot water heating system, there is a cylindrical pipe of length $28\ m$ and diameter $5\ cm$.
To do:
We have to find the total radiating surface in the system.
Solution:
Diameter of the pipe $= 5\ cm$
This implies,
Radius of the pipe $(r)=\frac{5}{2} \mathrm{~cm}$
Length of the pipe $(h)=28 \mathrm{~m}$
$=2800 \mathrm{~cm}$
Therefore,
The surface area of the pipe $=2 \pi r h$
$=2 \times \frac{22}{7} \times \frac{5}{2} \times 2800$
$=44000 \mathrm{~cm}^{2}$.
The total radiating surface in the system is $44000\ cm^2$.
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