# In a hot water heating system, there is a cylindrical pipe of length $28\ m$ and diameter $5\ cm$. Find the total radiating surface in the system.

Given:

In a hot water heating system, there is a cylindrical pipe of length $28\ m$ and diameter $5\ cm$.

To do:

We have to find the total radiating surface in the system.

Solution:

Diameter of the pipe $= 5\ cm$

This implies,

Radius of the pipe $(r)=\frac{5}{2} \mathrm{~cm}$

Length of the pipe $(h)=28 \mathrm{~m}$

$=2800 \mathrm{~cm}$

Therefore,

The surface area of the pipe $=2 \pi r h$

$=2 \times \frac{22}{7} \times \frac{5}{2} \times 2800$

$=44000 \mathrm{~cm}^{2}$.

**The total radiating surface in the system is $44000\ cm^2$.**

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