If the lateral surface of a cylinder is $ 94.2 \mathrm{~cm}^{2} $ and its height is $ 5 \mathrm{~cm} $, then find
(i) radius of its base
(ii) its volume. (Use $ \pi=3.14 $ ).

 Given:

The lateral surface of a cylinder is $94.2\ cm^2$ and its height is $5\ cm$.

To do:

We have to find

(i) radius of its base
(ii) its volume. 

Solution:

(i) Lateral surface area of the cylinder $= 94.2\ cm^2$

Height of the cylinder $(h)=5 \mathrm{~cm}$

Let $r$ be the radius of the cylinder.

Therefore,

$2 \pi r h=94.2$

$2 \times 3.14 \times r \times 5=94.2$

$r=\frac{94.2}{2 \times 3.14 \times 5}$

$=\frac{94.2}{31.4}$

$=3 \mathrm{~cm}$

The radius of its base is $3\ cm$.

(ii) Volume of the cylinder $=\pi r^{2} h$

$=3.14 \times 3^2 \times 5$

$=141.3 \mathrm{~cm}^{3}$ 

The volume of the cylinder is $141.3\ cm^3$.

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Updated on: 10-Oct-2022

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