If the volume of a right circular cone of height $ 9 \mathrm{~cm} $ is $ 48 \pi \mathrm{cm}^{3} $, find the diameter of its base.

Given: 

The volume of a right circular cone of height $9\ cm$ is $48 \pi\ cm^3$.

To do:

We have to find the diameter of its base.

Solution:

Height of the cone $h = 9\ cm$

Volume of the right circular cone $=48 \pi  cm^{3}$

This implies,

$\frac{1}{3} \pi r^{2} h =48 \pi$ 

$\frac{1}{3} \pi r^{2} \times 9 = 48 \pi$

$r^{2} = \frac{48}{3}$

$r^2= 16$

$r=\sqrt{16}$

$r= 4\ cm$

This implies,

Diameter of the base $=2r$

$=2\times4$

$=8\ cm$

Hence, the diameter of the right circular cone is $8\ cm$. 

Tutorialspoint

Simply Easy Learning

Updated on: 10-Oct-2022

137 Views

Kickstart Your Career

Get certified by completing the course

Get Started