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Find the volume of the right circular cone with
(i) radius $ 6 \mathrm{~cm} $, height $ 7 \mathrm{~cm} $
(ii) radius $ 3.5 \mathrm{~cm} $, height $ 12 \mathrm{~cm} $.
To do:
We have to find the volume of the right circular cone with
(i) radius \( 6 \mathrm{~cm} \), height \( 7 \mathrm{~cm} \)
(ii) radius \( 3.5 \mathrm{~cm} \), height \( 12 \mathrm{~cm} \).
Solution:
(i) Radius of the cone $(r) = 6\ cm$
Height of the cone $(h) = 7\ cm$
Therefore,
Volume of the cone $=\frac{1}{3} \pi r^{2} h$
$=\frac{1}{3} \times \frac{22}{7} \times 6 \times 6 \times 7$
$=264 \mathrm{~cm}^{3}$
The volume of the cone is $264\ cm^3$.
(ii) Radius of the cone $(r)=3.5 \mathrm{~cm}$
Height of the cone $(h)=12 \mathrm{~cm}$
Therefore,
Volume of the cone $=\frac{1}{3} \pi r^{2} h$
$=\frac{1}{3} \times \frac{22}{7} \times 3.5 \times 3.5 \times 12$
$=154 \mathrm{~cm}^{3}$
The volume of the cone is $154\ cm^3$.
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