If the common difference of an A.P. is 3, then$\ a_{20} -a_{15}$ is
$( A)\ 5$
$( B)\ 3$
$( C)\ 15$
$( D)\ 20$


Given: Common difference of an A.P., $d=3$

To do: To find out the value of $a_{20} -a_{15}=?$

Solution: let us say firrst term of A.P. is$a$.

As we know nth term of an A.P. with first term a and common difference d 

$n^{th}$ term of the given A.P.,$a_{n} =a\ +( n-1) d$

Then $a_{20} =a+( n-1) d$

$=a+( 20-1) \times 3$

$=a+57$

Similiarly $a_{15} =a+( 15-1) \times 3$

$=a+42$

$\therefore a_{20} -a_{15} =( a+57) -( a+42)$

$=a+57-a-42$

$=15$

$\therefore$Option $( C)$ is correct.

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Updated on: 10-Oct-2022

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