If the common difference of an A.P. is 3, then$\ a_{20} -a_{15}$ is
$( A)\ 5$
$( B)\ 3$
$( C)\ 15$
$( D)\ 20$
Given: Common difference of an A.P., $d=3$
To do: To find out the value of $a_{20} -a_{15}=?$
Solution: let us say firrst term of A.P. is$a$.
As we know nth term of an A.P. with first term a and common difference d
$n^{th}$ term of the given A.P.,$a_{n} =a\ +( n-1) d$
Then $a_{20} =a+( n-1) d$
$=a+( 20-1) \times 3$
$=a+57$
Similiarly $a_{15} =a+( 15-1) \times 3$
$=a+42$
$\therefore a_{20} -a_{15} =( a+57) -( a+42)$
$=a+57-a-42$
$=15$
$\therefore$Option $( C)$ is correct.
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