Find those values of $m$ the system of equation $2x+my-4=0;\ 3x-7y-10=0$, For which there is unique solution.

Given: Equations: $2x+my-4=0$;  $3x-7y-10=0$$.

To do: To find the value of $m$ for the unique solution.

Solution:

Given equations are: $2x+my-4=0$;     $3x-7y-10=0$.

For unique solution.

$\Rightarrow \frac{a_1}{a_2}≠\frac{b_1}{b_2}$

$\Rightarrow \frac{2}{3}≠\frac{m}{-7}$

$\Rightarrow 3m≠-7\times2$

 $\Rightarrow m≠-\frac{14}{3}$

Thus, for $m≠-\frac{14}{3}$, there is a unique solution.

Tutorialspoint

Updated on: 10-Oct-2022

20 Views

Kickstart Your Career

Get certified by completing the course

Get Started