Find the area of path of the following."

Given: A path in the figure.

To do: To find the area of the path.

Solution:

As given in the figure:

Length of the path $TUWV=AB=23\ m$

Breadth of the path $TUWV=TV=3\ m$

Therefore, area of the path $TUWV=length\times breadth$

$=23\times3$

$69\ m^2$

Similarly area of the path $PQRS=17\times3$

$=51\ m^2$

Area of $KLMN=3\times3$

$=9\ m^2$

$\therefore$ Total area of the path$=$Area of $TUVW+$Area of $PQRS-$Area of $KLMN$

$=69+51-9$

$=111\ m^2$

Thus, the area of the path is $101\ m^2$.
 

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Updated on: 10-Oct-2022

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