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In the following figures, find the area of the shaded portions:
"
$(i)$ Area of the rectangle$= l\times b$
$=18cm\times\left(6cm+4cm\right)$
$=18cm\times10cm=180cm^2$
Area of the right $\Delta BCE=\frac{1}{2}\times b\times h$
$=\frac{1}{2}\times8\times10=40\ cm^2$
Area of the shaded portion
$=180cm^2-70cm^2=110cm^2$
$(ii)$. Area of the square $PQRS= \left(Side\right)^2$
$=\left(20\right)^2=400cm^2$
Area of triangle$=\ \frac{1}{2}\times b\times h$
$\frac{1}{2}\times10\times10=50cm^2$
Area of triangle$=\ \frac{1}{2}\times b\times h$
$=\frac{1}{2}\times10\times20=100cm^2$
Area of triangle$=\ \frac{1}{2}\times b\times h$
$=\frac{1}{2}\times10\times20=100cm^2$
Area of the three triangles
$=50cm^2+100cm^2+100cm^2=250cm^2$
Area of the shaded portion
$=400cm^2-250cm^2=150cm^2$
Updated on: 10-Oct-2022
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