Construct a triangle whose perimeter is $6.4\ cm$, and angles at the base are $60^o$ and $45^o$.
Given:
A triangle whose perimeter is $6.4\ cm$, and angles at the base are $60^o$ and $45^o$.
To do:
We have to construct the given triangle.
Solution:
Steps of construction:
(i) Draw a line segment $PQ = 6.4\ cm$.
(ii) At $P$ draw a ray $PX$ making an angle of $60^o$ and at $Q$, a ray $QY$ making an angle of $45^o$.
(iii) Draw the bisector of $\angle P$ and $\angle Q$ meeting each other at $A$.
(iv) Draw the perpendicular bisectors of $PA$ and $QA$ intersecting $PQ$ at $B$ and $C$ respectively.
(v) Join $AB$ and $AC$.
Therefore,
$\triangle ABC$ is the required triangle.
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