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A student while heating solid lead nitrate taken in a test-tube would observe :
(1) white residue of PbO2 | (2) green residue of NO2 |
(3) yellow residue of PbO | (4)brown residue of NO |
Correct answer: (3) yellow residue of PbO
Explanation: When solid lead nitrate is heated, a yellow residue (lead oxide) is obtained, along with brown colored gas (nitrogen dioxide), and oxygen is liberated.
The chemical equation for the above reaction is given below:
$2Pb(NO_3)_2→2PbO + 4NO_2 + O_2$
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