A hammer of mass 500 g , moving at 50 m s-1 , strikes a nail . The nail stops the hammer in a very short timeof 0.01 s. What is the force of nail on the hammer?

Given: Mass of the hammer, m= 500 g = 0.5 kg

Initial velocity of the hammer, u= 50 m/s 

Time taken by the nail to the stop the hammer, t = 0.01 s 

To find: We have to find the force of the nail on the hammer.

Solution: 

Final Velocity of the hammer, v= 0 (since the hammer finally comes to rest) 

$F = \frac{m(v-u)}{t}$

$F = \frac{0.5(0-50)}{ 0.01}$

$F\ =\ 0.5\ \times \ 50\ \times \ 100\ =\ -2500N$

-ve sign indicates the force of nail on the hammer moving in the opposite direction to that of hammer movement.

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Updated on: 10-Oct-2022

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