A dealer sold two types of goods for 10000 each. One of them he lost 20% and on the other he gained 20%. Find his gain or loss percent in the entire transaction.


Given :

A dealer sold two types of goods for 10000 each.

One of them he lost 20% and on the other, he gained 20%. 

To do :

We have to find the loss or gain % in the whole transaction.

Solution :


 Let the cost price of the first item be 'a', and sold it for a 20% loss.

The selling price of the first item $= ₹10000$

Since it sold for a loss of 20%, $80$% of a $=10000$

                                                  $\frac{80}{100}  a = 10000$

                                                  $\frac{4}{5} a = 10000$

                                                  $a = 10000 \times \frac{5}{4}$

                                                  $a = 12500$

Therefore, the cost price of the first item$=12500$.

Let the cost price of the second item be 'b', and sold it for 20% profit.

The selling price of the second item $= ₹10000$

Since it sold for a profit of 20%, $120$% of b $=10000$

                                                  $\frac{120}{100}  b = 10000$

                                                  $\frac{6}{5} b = 10000$

                                                  $a = 10000 \times \frac{5}{6}$

                                                  $a = 8333$

Therefore, the cost price of the second item$=8333$.

The total cost price $= 12500 + 8333 = 20833$

Total selling price $=10000 + 10000 = 20000$

The amount Loss $=$ Total cost price $-$ Total selling price

                                $ = 20833 - 20000 = 833$

Loss % $= \frac{833}{20000} \times 100$

            $ = 4.165$

Therefore, there was a loss of 4.165% on the entire transaction.


                                  

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Updated on: 10-Oct-2022

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