A cylindrical vessel, without lid, has to be tin-coated on its both sides. If the radius of the base is $70\ cm$ and its height is $1.4\ m$, calculate the cost of tin-coating at the rate of $Rs.\ 3.50$ per $1000\ cm^2$.
Given:
A cylindrical vessel, without lid, has to be tin-coated on its both sides.
The radius of the base is $70\ cm$ and its height is $1.4\ m$.
To do:
We have to find the cost of tin-coating at the rate of $Rs.\ 3.50$ per $1000\ cm^2$.
Solution:
Radius of the base of the cylindrical vessel $(r) = 70\ cm$
Height of the cylinder $(h) = 1.4\ m$
$= 1.4\times100\ cm$
$=140\ cm$
Total surface area (excluding upper lid) on both sides $= 2 \pi rh \times 2 + \pi r^2 \times 2$
$=4 \pi r h+2 \pi r^{2}$
$=\pi r(4 h+2 r)$
$=\frac{22}{7} \times 70[4 \times 140+70 \times 2]$
$=220[560+140]$
$=220 \times 700$
$=154000 \mathrm{~cm}^{2}$
Rate of tin coating $= Rs.\ 3.50$ per $1000 \mathrm{~cm}^{2}$
Total cost of coating $=\frac{154000 \times 3.50}{1000}$
$=Rs.\ 154 \times 3.50$
$=Rs.\ 539$
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