A car is travelling at a speed of $90\ km/h$. Brakes are applied so as to produce a uniform acceleration of $0.5 m/s^2$. Find how far the car will go before it is brought to rest?a). 8100 m b). 900 mc). 625 m d). 620 m

Here, initial velocity $u=90\ km/h=90\times\frac{5}{18}\ m/s=25\ m/s$

Final velocity $v=0$

Acceleration $a=-0.5\ m/s^2$

Let $s$ be the distance traveled by car before it stops.

On using the equations $v^2=u^2+2as$

$0^2=25^2+2\times(-0.5)\times s$

$0=625-s$

Or $s=625\ m$

Therefore, option c is correct.

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Updated on: 10-Oct-2022

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