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A motorcycle is being driven at a speed of $20\ m/s$ when brakes are applied to bring it to rest in five seconds. The deceleration produced in this case will be:
(a).\ +4\ m/s^2$
(b).\ -4\ m/s^2$
(c).\ +0.25\ m/s^2$
(d).\ -0.25\ m/s^2$
Here given, initial velocity $u=20\ m/s$
Final velocity $v=0$
Time $t=5\ s$
Therefore, deceleration $=-$acceleration
$=-(\frac{v-u}{t})$
$=-(\frac{0-20}{5})$
$=-(-4\ m/s)
$=+4\ m/s$
So, option (a) is correct.
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