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A car is moving on a straight road with uniform acceleration. The speed of the car varies with time as follows:
Time(s) | 0 | 2 | 4 | 6 | 8 | 10 |
Speed(m/s) | 4 | 8 | 12 | 16 | 20 | 24 |
Draw the speed-time graph by choosing a convenient scale.
From this graph:
(i) Calculate the acceleration of the car.
(ii) Calculate the distance travelled by the car in 10 seconds."
Speed-time graph of the moving car is as below:
(i). Acceleration of the car $=$slope AB$=\frac{24-4}{10-0}$
$=\frac{20}{10}$
$=2\ m/s^2$
(ii). Distance traveled by car is equal to the area of trapezium OABC.
$=\frac{1}{2}\times(OA+BC)\times OC$
$=\frac{1}{2}\times(4+24)\times10$
$=\frac{1}{2}\times28\times10$
$=140\ m$
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